Center of gravity of two distinct shapes Pt2

CENTER OF GRAVITY OF TWO DISTINCT SHAPES PT2

INTRODUCTION

The center of gravity COG of an object is the point of action of the gravitational force. It is also known as the balancing point since all objects [simple or complex] have their COG within the object’s sphere of influence and this ensures stability. There are two values to be noted which is the geometrical center of gravity and the actual center of gravity. The geometrical COG is the exact center of the object. It can be calculated by various available methods like summation, moment of inertia, etc. The geometrical COG is valid as long as there is uniform distribution of mass and or uniform gravitational field. In case of uneven mass distribution or use of composite or heterogeneous materials, the actual COG will no longer coincide with the geometrical COG. This is because mass is distributed unevenly and the COG will shift where there is more mass. In this article we intend to determine the COG of an assembly of an isosceles triangle and a semi-circle.

ASSUMPTIONS

1. Mass of the object is evenly distributed

2. The gravitational field is uniform

3. The semi-circle accurately fits inside the triangle

CALCULATION

Consider a semi-circle inscribed in an isosceles triangle such that the diameter of the semi-circle coincides with the base of the isosceles triangle. This orientation is represented in figure.1. The triangle has height ‘h’, side length ‘b’ and base ‘a’. The diameter of the semi-circle is connected to the base of the triangle, hence the diameter is ‘a’ and thereby the radius is ‘a/2’ or ‘r’ where r = a/2

Fig .1 Triangle and semi-circle

We will determine the center of gravity using the area moment of inertia method. We need to follow four steps:

1    1. Determine the distance between the x coordinate of C.O.G. of (triangle and semi-circle) and reference Y axis.

2    2. Determine the distance between the y coordinate of C.O.G. of (triangle and semi-circle) and reference X axis.

3      3. Determine the area of two objects in question.

4      4. Use the Summation equation to determine the C.O.G. coordinates.

It is evident that the assembly represented in figure.1 is symmetric about y axis, hence x coordinates of both triangle and semi-circle will be their midpoint. The y coordinates are same for isosceles triangle and semi-circle.

The coordinates and areas of triangle and semi-circle are as follows

Isosceles triangle

X₁ = r, Y₁ = h/3

A₁ = (1/2)*2r*h = h*r

Semi-circle

X₂ = r, Y₂ = 4r/3π

A­₂ = (1/2)*π*r² = πr²/2

Center of gravity

The center of gravity coordinates x and y of the assembly can be computed by using the formula,

Negative sign in above equations indicate that the second part (semi-circle) is being subtracted from the whole assembly.

CONCLUSION

Thus the center of gravity of the given assembly is located at 

Center of gravity of two distinct shapes Pt1

CENTER OF GRAVITY OF TWO DISTINCT SHAPES PT1

INTRODUCTION

The center of gravity COG of an object is the point of action of the gravitational force. It is also known as the balancing point since all objects [simple or complex] have their COG within the object’s sphere of influence and this ensures stability. There are two values to be noted which is the geometrical center of gravity and the actual center of gravity. The geometrical COG is the exact center of the object. It can be calculated by various available methods like summation, moment of inertia, etc. The geometrical COG is valid as long as there is uniform distribution of mass and or uniform gravitational field. In case of uneven mass distribution or use of composite or heterogeneous materials, the actual COG will no longer coincide with the geometrical COG. This is because mass is distributed unevenly and the COG will shift where there is more mass. In this article we intend to determine the COG of an assembly of an isosceles triangle and a semi-circle.

ASSUMPTIONS

1. Mass of the object is evenly distributed

2. The gravitational field is uniform

CALCULATION

Consider an assembly of an isosceles triangle and a semi-circle in an orientation as shown in figure.1. The triangle has height ‘h’, side length ‘b’ and base ‘a’. The diameter of the semi-circle is connected to the base of the triangle, hence the diameter is ‘a’ and thereby the radius is ‘a/2’ or ‘r’ where r = a/2

Fig .1 An isosceles triangle and a semi-circle

We will determine the center of gravity using the area moment of inertia method. We need to follow four steps:

1    1. Determine the distance between the x coordinate of C.O.G. of (triangle and semi-circle) and reference Y axis.

2    2. Determine the distance between the y coordinate of C.O.G. of (triangle and semi-circle) and reference X axis.

3       3. Determine the area of two objects in question.

4       4. Use the Summation equation to determine the C.O.G. coordinates.

It is evident that the assembly represented in figure.1 is symmetric about y axis, hence x coordinates of both triangle and semi-circle will be their midpoint. The y coordinates are same for isosceles triangle and semi-circle.

The coordinates and areas of triangle and semi-circle are as follows

Isosceles triangle

X₁ = r, Y₁ = h/3

A₁ = (1/2)*2r*h = h*r

Semi-circle

X₂ = r, Y₂ = 4r/3π

A­₂ = (1/2)*π*r² = πr²/2

Center of gravity

The center of gravity coordinates x and y of the assembly can be computed by using the formula,

CONCLUSION

Thus the center of gravity of the given assembly is located at