TIME
DILATION IN EQUATOR VERSUS POLE OF EARTH
INTRODUCTION
Earth is the 3rd
planet in our Solar System. It completes one rotation about its axis in 23
hours 56 minutes and 4 second. Consider three locations on our planet Earth,
the center, equator and the North Pole. All points rotate with the same angular
velocity but the center doesn’t have a tangential velocity. According to the
Special Theory of Relativity, a clock on Earth’s equator would run slower than
that on the pole with respect to the center. We’ll find the time gained by equator
and pole relative to the stationary center.
ASSUMPTIONS
1. Earth is not revolving around the Sun.
2. The effect of
Gravitational time dilation is negligible.
CALCULATION
The Angular velocity is given by,
ω = 2π/T [rad/s]
T – Rotational time
period [T ≈ 24 hours = 86400s]
ω = 2*3.14/86400
ω = 7.2722*10-5
rad/s
The angular velocity is
same at all points on earth since it doesn’t exhibit differential rotation. But
the tangential velocity on surface varies with the distance from the center.
The tangential velocity
at the center is given by,
v = R*ω [m/s]
R – Average radius of
earth [R = 0m][center]
v = 0*7.2722*10-5
v = 0 m/s
Since tangential
velocity is zero, time won’t dilate hence is absolute. We’ll consider time at
the center for reference.
The tangential velocity
at the equator is given by,
v = R*ω [m/s]
R – Equatorial radius
of earth [R = 6378.13 km]
v = 6378.13*1000*7.2722*10-5
v = 463.8303 m/s
The tangential velocity
at the North Pole is given by,
v = R*ω [m/s]
R – Polar radius of circular motion
R = 0 since the axis of pole passes through the center of Earth
R = 0 since the axis of pole passes through the center of Earth
v = 0*1000*7.2722*10-5
v = 0 m/s
According to the
Special Theory of Relativity, the time dilation equation is,
t' = t/γ [s]
t’ – Actual time or Moving observer’s time. [s]
t - Proper time or Stationary observer’s time. [s]
γ – Relativistic gamma
factor, γ = 1/√ [1-(v/c) 2]
c - Velocity of light
[c = 3*108 m/s]
The time dilation at
Equator is,
t' = t*√ [1-(v/c)
2]
t' = t*√ [1-2.3904*10-12]
t' = t*√ [0.99999999999761]
t' = t * 0.999999999998805
The time dilation at
Pole is,
t' = t*√ [1-(v/c)
2]
t' = t*√ [1-0]
t' = t*√ [1]
t' = t*
CONCLUSION
We can observe that pole and equatorial time isn’t the same which proves that time dilates only on equator and not on pole or center. We’ll consider 5 different t’ values and calculate the t value. The larger the t’ the more is the difference between t and t’. Thus equatorial region will gain around 37 microsecond than the polar region or center in one year.
Time
|
t’
[Center of Earth] (s)
|
t
[Pole] (s)
|
t
[Equator] (s)
|
||
1
minute
|
60
|
60
|
|
||
1
hour
|
3600
|
|
|
||
1
day
|
86400
|
86400
|
|
||
1
month
|
2592000
|
|
|
||
1
year
|
31536000
|
31536000
|
|
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