GRAVITATIONAL FIELD OF A TRIANGLULAR PLATE

GRAVITATIONAL FIELD OF A TRIANGLULAR PLATE

INTRODUCTION

Gravity is derived from the Latin word ‘gravitas’ meaning mass. The universal law of gravitation was coined by Sir Isaac Newton. According to the law, any two masses anywhere in the universe separated by a distance will attract each other. This force of attraction is proportional to the product of their masses and inversely proportional to square of the distance between them.

(Eq. 1)

The distance between two masses can be finite or infinite, which is why gravitational force is referred to as long range force but is also the weakest force among all the other fundamental forces. All objects that have mass will attract other masses. This means that each mass has its own gravitational field just like Earth. So this implies that all objects will attract each other since they will have their own field. This is not evident on Earth since Earth’s gravitational field outweighs all other mass’s field and hence all objects no matter how massive are attracted toward the Earth. In this post we intend to determine the gravitational field of a two dimensional Triangular plate and identify points where the plate’s own gravity is strong at some parts and weak at the other. 

ASSUMPTIONS

1. The thickness of the plate is negligible compared to its length and width.

2. The plate is not under the influence of an external gravitational field.

3. The plate is a homogeneous material.

4. All the mass is assumed to be concentrated at the center.

CALCULATION

Consider a Triangle plate of length ‘a’ [m] and mass M [Kg]. We will first determine the center of gravity of this plate and then the magnitude of the gravitational field at points of interest.

Center of gravity

Fig 1 Triangle plate

The center of gravity of an Isosceles Triangle of base ‘b’ and height ‘h’ is (x,y) ≡ (b2, h/3)

Points of interest and their distances from center

We will consider two points namely the corner and midpoint of a side.

Point A ≡ (0, 0) or (b, 0)

The distance between Point A and C.G. can be calculated by the distance formula

 

Point B ≡ (b/2, 0)

The distance between Point B and C.G. can be calculated by the distance formula

Point D ≡ (b/2, h)

The distance between Point D and C.G. can be calculated by the distance formula

Gravitational field

From Eq. 1, the force of attraction between a mass and its own surface is given by,

g – Acceleration due to gravity of the mass (m/s²)

G – Universal constant of gravitation

G = 6.67*10^-11 Nm²/Kg²

M – Mass of the object (Kg)

R – Distance between the centers of two masses (m)

G field at point A

The gravitational field beyond the surface is obtained by adding the additional distance,

d – Distance from the surface of the object to other object.

G field at point B

The gravitational field beyond the surface is obtained by adding the additional distance,

G field at point D

The gravitational field beyond the surface is obtained by adding the additional distance,

CONCLUSION

We thus determined the magnitude of gravitational field at various points on a Triangle plate. We observe that gravitational field is strongest at point B, less intense at point D and weakest at point A. This is because point B is closest to the centroid while point D and A are farther away. This implies that point B is attracted more toward the center because of its closer distance than point A or point D which is slightly far away from the center.