SIMPLE PENDULUM ON JUPITER
INTRODUCTION
Jupiter
is the fifth planet in our Solar System. Consider a simple pendulum on the
surface of Jupiter ready to swing. A pendulum is a weight suspended from a
pivot so that it can swing freely. It has a bob [mass] suspended from a
frictionless pivot via a string. The central position of the bob i.e. when the
pendulum is at rest is called its Mean position. When the bob is made to swing
on the application of external force, it oscillates back and forth about this
mean position. The maximum distance traversed by the bob from the mean position
is known as amplitude. The amplitude is measured in radians which is a unit of
angle. The time taken by the pendulum to complete one full oscillation is
called the Time Period. For small amplitude less than 1 radian, the time period
is independent of amplitude of the pendulum. We intend to determine the time
period of such a pendulum on Jupiter.
ASSUMPTIONS
1. The string has no tension or compression
2. The pendulum is indestructible
3. Air resistance is negligible
4. Wind resistance is also negligible
5. Effect of
Gravitational Time dilation is negligible
CALCULATION
The
time period of a simple pendulum is given by,
T =
2π*√ (l/g) (Eqn. 1)
Where,
T –
Time period [s]
l –
Length of the pendulum [m]
g –
Acceleration due to gravity on Jupiter [m/s2]
g =
24.5 m/s2 (Eqn. 2)
Let
the length of pendulum be
l =
1 m (Eqn. 3)
Now
substitute equations (2), (3) in equation (1)
T = 2π*√ (1/24.5)
T = 2π*√ (0.0408)
T = 2π*0.2020
T = 1.2693 s (Eqn.
4)
This
is the time period of a simple pendulum on Jupiter. It means any pendulum
performing small oscillations will always take approximately 1.3 second to
complete one cycle anywhere on Jupiter provided the value of gravity is same
everywhere and the effects of friction are neglected. Due to higher gravity of
Jupiter, the time period of pendulum is less compared to Earth where it was 2
second.
CONCLUSION
We
thus determined the time period of a simple pendulum on Jupiter.
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