SIMPLE PENDULUM ON ISS
INTRODUCTION
The
International Space Station [ISS] is a satellite orbiting earth at
approximately 250 miles from the surface. Consider a pendulum aboard the ISS. A
pendulum is a weight suspended from a pivot so that it can swing freely. It has
a bob [mass] suspended from a frictionless pivot via a string. The central
position of the bob i.e. when the pendulum is at rest is called its Mean
position. When the bob is made to swing on the application of external force,
it oscillates back and forth about this mean position. The maximum distance
traversed by the bob from the mean position is known as amplitude. The
amplitude is measured in radians which is a unit of angle. The time taken by
the pendulum to complete one full oscillation is called the Time Period. For
small amplitude less than 1 radian, the time period is independent of amplitude
of the pendulum. We intend to determine the time period of such a pendulum on ISS.
The ISS is always in a state of free fall hence all objects inside ISS will
experience weightlessness.
A simple pendulum |
ASSUMPTIONS
1. The string has no tension or compression
2. The pendulum is indestructible
3. Air resistance is negligible
CALCULATION
The
time period of a simple pendulum is given by,
T =
2π*√ (l/g) (Eqn. 1)
Where,
T –
Time period [s]
l –
Length of the pendulum [m]
g –
Acceleration due to gravity on ISS [m/s2]
g =
0 m/s2 {due to free fall} (Eqn. 2)
Let
the length of pendulum be
l =
1 m (Eqn. 3)
Now substitute
equations (2), (3) in equation (1)
T = 2π*√ (1/0)
T = 2π*√ (∞)
T = 2π*∞
T = ∞ s (Eqn. 4)
This
is the time period of a simple pendulum on ISS. This clearly indicates that
Time period does not exist for the pendulum inside ISS. Even when a small force
is applied to the bob, the bob will just move in one direction and never return
to the mean position due to lack of gravity.
CONCLUSION
We
thus concluded that the pendulum will not work aboard the ISS due to lack of
gravity.
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